0=4m^2-4m-3

Solution for 0=4m^2-4m-3 equation:

0=4m^2-4m-3

We move all terms to the left:

0-(4m^2-4m-3)=0

We add all the numbers together, and all the variables

-(4m^2-4m-3)=0

We get rid of parentheses

-4m^2+4m+3=0

a = -4; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·(-4)·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*-4}=\frac{-12}{-8}
=1+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*-4}=\frac{4}{-8}
=-1/2
$